(1/64)^2k=8^-3k

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Solution for (1/64)^2k=8^-3k equation: 



(1/64)^2k=8^-3k

We move all terms to the left:

(1/64)^2k-(8^-3k)=0



Domain of the equation: 64)^2k!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+1/64)^2k-(8^-3k)=0

We get rid of parentheses

(+1/64)^2k+3k-8^=0

We multiply all the terms by the denominator


(+1+3k*64)^2k-8^*64)^2k=0

We add all the numbers together, and all the variables

(3k*64+1)^2k-8^*64)^2k=0

Wy multiply elements

-512k^2+(3k*64+1)^2k=0

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